3.2.99 \(\int \frac {x^2}{(a+b x)^4} \, dx\)

Optimal. Leaf size=17 \[ \frac {x^3}{3 a (a+b x)^3} \]

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Rubi [A]  time = 0.00, antiderivative size = 17, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {37} \begin {gather*} \frac {x^3}{3 a (a+b x)^3} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^2/(a + b*x)^4,x]

[Out]

x^3/(3*a*(a + b*x)^3)

Rule 37

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n +
1))/((b*c - a*d)*(m + 1)), x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && EqQ[m + n + 2, 0] && NeQ
[m, -1]

Rubi steps

\begin {align*} \int \frac {x^2}{(a+b x)^4} \, dx &=\frac {x^3}{3 a (a+b x)^3}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 31, normalized size = 1.82 \begin {gather*} -\frac {a^2+3 a b x+3 b^2 x^2}{3 b^3 (a+b x)^3} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^2/(a + b*x)^4,x]

[Out]

-1/3*(a^2 + 3*a*b*x + 3*b^2*x^2)/(b^3*(a + b*x)^3)

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^2}{(a+b x)^4} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[x^2/(a + b*x)^4,x]

[Out]

IntegrateAlgebraic[x^2/(a + b*x)^4, x]

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fricas [B]  time = 1.04, size = 54, normalized size = 3.18 \begin {gather*} -\frac {3 \, b^{2} x^{2} + 3 \, a b x + a^{2}}{3 \, {\left (b^{6} x^{3} + 3 \, a b^{5} x^{2} + 3 \, a^{2} b^{4} x + a^{3} b^{3}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/(b*x+a)^4,x, algorithm="fricas")

[Out]

-1/3*(3*b^2*x^2 + 3*a*b*x + a^2)/(b^6*x^3 + 3*a*b^5*x^2 + 3*a^2*b^4*x + a^3*b^3)

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giac [A]  time = 1.27, size = 29, normalized size = 1.71 \begin {gather*} -\frac {3 \, b^{2} x^{2} + 3 \, a b x + a^{2}}{3 \, {\left (b x + a\right )}^{3} b^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/(b*x+a)^4,x, algorithm="giac")

[Out]

-1/3*(3*b^2*x^2 + 3*a*b*x + a^2)/((b*x + a)^3*b^3)

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maple [B]  time = 0.00, size = 41, normalized size = 2.41 \begin {gather*} -\frac {a^{2}}{3 \left (b x +a \right )^{3} b^{3}}+\frac {a}{\left (b x +a \right )^{2} b^{3}}-\frac {1}{\left (b x +a \right ) b^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2/(b*x+a)^4,x)

[Out]

a/b^3/(b*x+a)^2-1/3*a^2/b^3/(b*x+a)^3-1/b^3/(b*x+a)

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maxima [B]  time = 1.40, size = 54, normalized size = 3.18 \begin {gather*} -\frac {3 \, b^{2} x^{2} + 3 \, a b x + a^{2}}{3 \, {\left (b^{6} x^{3} + 3 \, a b^{5} x^{2} + 3 \, a^{2} b^{4} x + a^{3} b^{3}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/(b*x+a)^4,x, algorithm="maxima")

[Out]

-1/3*(3*b^2*x^2 + 3*a*b*x + a^2)/(b^6*x^3 + 3*a*b^5*x^2 + 3*a^2*b^4*x + a^3*b^3)

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mupad [B]  time = 0.09, size = 56, normalized size = 3.29 \begin {gather*} -\frac {a^2+3\,a\,b\,x+3\,b^2\,x^2}{3\,a^3\,b^3+9\,a^2\,b^4\,x+9\,a\,b^5\,x^2+3\,b^6\,x^3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2/(a + b*x)^4,x)

[Out]

-(a^2 + 3*b^2*x^2 + 3*a*b*x)/(3*a^3*b^3 + 3*b^6*x^3 + 9*a^2*b^4*x + 9*a*b^5*x^2)

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sympy [B]  time = 0.30, size = 56, normalized size = 3.29 \begin {gather*} \frac {- a^{2} - 3 a b x - 3 b^{2} x^{2}}{3 a^{3} b^{3} + 9 a^{2} b^{4} x + 9 a b^{5} x^{2} + 3 b^{6} x^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2/(b*x+a)**4,x)

[Out]

(-a**2 - 3*a*b*x - 3*b**2*x**2)/(3*a**3*b**3 + 9*a**2*b**4*x + 9*a*b**5*x**2 + 3*b**6*x**3)

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